4a^2+13a+6=0

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Solution for 4a^2+13a+6=0 equation: 



4a^2+13a+6=0

a = 4; b = 13; c = +6;
Δ = b2-4ac
Δ = 132-4·4·6
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{73}}{2*4}=\frac{-13-\sqrt{73}}{8}
$


$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{73}}{2*4}=\frac{-13+\sqrt{73}}{8}
$

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